For the equation, N2+3H2 = 2NH3 where the Kp is 4.3×10^-4 at 375°C. Calculate the Kc for the equation

1 answer

The relationship between Kp and Kc is:

Kp = Kc(RT)^Δn

where R is the gas constant (0.0821 L·atm/mol·K), T is the temperature in Kelvin, and Δn is the difference between the sum of the stoichiometric coefficients of the products and the sum of the stoichiometric coefficients of the reactants.

For the equation N2 + 3H2 = 2NH3, Δn = (2 - 1) = 1.

At 375°C (648.15 K), we have:

Kp = 4.3×10^-4 = Kc(RT)^Δn
Kc = Kp/RT = (4.3×10^-4)/(0.0821)(648.15)^1
Kc = 5.8×10^-7

Therefore, the Kc for the equation N2 + 3H2 = 2NH3 is 5.8×10^-7 at 375°C.