insert into the equation for x, two. Then solve for y.
16+y^2=48+4y
y^2-4y-32=0
(y-8)(y+4)=-
y=8, or -4 when x=2
For the curve given by 4x^2 + y^2 = 48 + 2 * x * y, find the positive y-coordinate given that the x-coordinate is 2.
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