The balanced chemical equation for the combustion of ethane (CH3CH3) is:
2CH3CH3 + 7O2 -> 4CO2 + 6H2O
This equation tells us that for every 2 moles of ethane, we need 7 moles of oxygen to completely burn the ethane.
Since we have 0.27 mole of ethane, we need to determine how many moles of oxygen are required. We can set up a proportion:
2 mol CH3CH3 / 7 mol O2 = 0.27 mol CH3CH3 / x mol O2
Solving for x, we get:
x = (7 mol O2)(0.27 mol CH3CH3) / 2 mol CH3CH3
x = 0.945 mol O2
Therefore, we need 0.945 moles of O2 to completely consume 0.27 mole of CH3CH3.
For the combustion of ethane, beginning with 0.27 mole of CH3 CH3.
how many moles of O₂ are required to completely consume the CH3 CH3?
1 answer