For the cell diagram
Pt(s)|H2(g)|H+(aq)||Cu2+(aq)|Cu(s)
Write a balanced equation for the half-reaction at the cathode.
The cathode is the site of reduction so copper gets reduced.
So wouldn't the answer be:
Cu2+(aq) -> Cu(s) + 2e-?
1 answer
the cathode is the site of reduction..but you should check your equation: Note that reduction can be characterized by the gaining of electrons.