For the cell diagram

Pt(s)|H2(g)|H+(aq)||Cu2+(aq)|Cu(s)

Write a balanced equation for the half-reaction at the cathode.

The cathode is the site of reduction so copper gets reduced.

So wouldn't the answer be:

Cu2+(aq) -> Cu(s) + 2e-?

1 answer

the cathode is the site of reduction..but you should check your equation: Note that reduction can be characterized by the gaining of electrons.