Here is a solved simple stoichiometry problem. You have a limiting reagent problem. The way I solve these is to solve two simple stoichiometry problems, one for each of the reagent you are given. You will get two different amounts (moles) of product formed; the correct answer in limiting reagent problem is ALWAYS the smaller one and the reagent providing that value is the limiting reagent.
http://www.jiskha.com/science/chemistry/stoichiometry.html
For the balanced equation shown below, if 40.1 grams of C2H3O2Br were reacted with 8.01 grams of O2, how many grams of H2O would be produced?
2C2H3O2Br+O2->4CO+2H2O+2HBr
Thank you!
1 answer