length = circumference of roller = 2π(8) = 16π
width = 30
area = 30(16π) = 480π in^2
For small paving jobs, a contractor uses a roller pushed by a worker.
A roller pushed by a worker (radius=8 in; length=30 in.)
To the nearest square inch, what is the area of pavement with which the surface of the roller will come into contact in one complete rotation?
A 753 in.²
B 1,507 in.²
C 1,708 in.²
D 1,909 in.²
2 answers
=2(pi)rh
=2(pi)(8)(30)
=1507 in^2
So the answer is B
=2(pi)(8)(30)
=1507 in^2
So the answer is B
1 answer