total mass = .14 +.47 = .61 kg
weight = .61*9.81
friction force = .5 * .61 * 9.81
work done = force * distance = .5*.61*9.81*6.8
so
(1/2)(.61) v^2 = .5 * .61 * 9.81*6.8
where v is initial speed of can with pellet
v^2 = 9.81*6.8
solve for v
now conservation of momentum
u is pellet speed
.14 u = .61 v
For shooting practice a person uses a pellet gun and an empty pop can. The pop can rests on a flat surface that has a coefficient of kinetic friction 0.500. The pellet has a mass of 0.140 kg and the pop can has a mass of 0.470 kg. After the pellet is fired and now inside the pop can they slide together for 6.80 m. What was the speed of the pellet?
1 answer
1 answer