For renting tables, Parties ‘R Us charges, C

, a $60 delivery fee and $4 per table, t
. Rob’s Rentals charges, C
, a $40 delivery fee and $6 per table, t
. Write the pair of linear equations that model this situation.(1 point)
Responses

Parties ‘R Us: C=60t+6
; Rob’s Rentals: C=40t+4
Parties ‘R Us: upper C equals 60 t plus 6 ; Rob’s Rentals: upper C equals 40 t plus 4

Parties ‘R Us: C=60t+4
; Rob’s Rentals: C=40t+6
Parties ‘R Us: upper C equals 60 t plus 4 ; Rob’s Rentals: upper C equals 40 t plus 6

Parties ‘R Us: C=4t+60
; Rob’s Rentals: C=6t+40
Parties ‘R Us: upper C equals 4 t plus 60 ; Rob’s Rentals: upper C equals 6 t plus 40

Parties ‘R Us: C=4t+40
; Rob’s Rentals: C=6t+60

1 answer

To model the situation, we need to represent the total cost \( C \) for each rental service in terms of the number of tables \( t \).

For Parties ‘R Us:

  • The delivery fee is $60, and the cost per table is $4. Thus, the equation for Parties ‘R Us is: \[ C = 4t + 60 \]

For Rob's Rentals:

  • The delivery fee is $40, and the cost per table is $6. Thus, the equation for Rob's Rentals is: \[ C = 6t + 40 \]

So the pair of linear equations that model this situation is:

  • Parties ‘R Us: \( C = 4t + 60 \)
  • Rob’s Rentals: \( C = 6t + 40 \)

Based on the options provided, the correct response is: Parties ‘R Us: \( C = 4t + 60 \); Rob’s Rentals: \( C = 6t + 40 \).