I don't like to type all that stuff, so propanoic acid I will call HP.
HP ==> H^+ + P^-
Ka = (H^+)(P^-)/(HP)
H^+ = x
P^- = x
HP = 0.170-x
Substitute into Ka and solve for x, then convert to pH.
% diss = [(H^+)/0.170]*100 = ??
Post your work if you get stuck.
For propanoic acid (HC3H5O2, Ka = 1.3 10-5), determine the concentration of all species present, the pH, and the percent dissociation of a 0.170 M solution.
PLEASE HELP ME DO THIS PROBLEM.
2 answers
For propanoic acid (HC3H5O2, Ka = 1.3 10-5), determine the concentration of all species present, the pH, and the percent dissociation of a 0.170 M solution.
[HC3H5O2]:
[C3H5O2‾]:
[H+] :
[OH ‾]:
pH :
i need help on how to find the concentration of these also in Moles.
[HC3H5O2]:
[C3H5O2‾]:
[H+] :
[OH ‾]:
pH :
i need help on how to find the concentration of these also in Moles.