For △NPQ, QN=10, QP=7, and PN=14. What is the order of the angles of △NPQ from largest to smallest?

Question

A. ∠Q, ∠P, ∠N
B. ∠N , ∠Q , ∠P
C. ∠P , ∠Q , ∠N
D. ∠N, ∠P, ∠Q

Answer 1

To determine the order of the angles from largest to smallest in △NPQ, we need to compare the side lengths and apply the triangle inequality theorem.

Since QN=10, QP=7, and PN=14, the longest side is PN, the shortest side is QP, and the third side is NQ.

Therefore, the order of the angles from largest to smallest is: ∠N, ∠P, ∠Q

The answer is:

B. ∠N, ∠P, ∠Q