these questions just takes some common sense. At the highest point, the vertical speed is zero. So all that's left is the horizontal speed, which is constant at
10 cos53°
Due to conservation of momentum, the speed at impact is exactly the same as the speed at takeoff.
Note that I am not referring to velocity, which also includes the direction.
for my science class we went over questions like this, I was hoping someone could help me figure this out,and give me the basic equations for problems like these..
A ball is shot into the air with initial speed of 10 m/s at an angle of 53°.
(a) What is the object's speed at the highest point in its trajectory?
b)What is the object's speed just before it strikes the ground?
1 answer