For its size, the common flea is one of the most accomplished jumpers in the animal world. A 2.30 mm -long, 0.540 mg critter can reach a height of 18.0 cm in a single leap.
a) Neglecting air drag, what is the takeoff speed of such a flea?
-i got 1.88m/s
b) Calculate the kinetic energy of this flea at takeoff and its kinetic energy per kilogram of mass.
-wouldn't we just use KE = 1/2mv^2 cause i got 9.54e-4 J but it says my answer is wrong
2 answers
nvm i got it, kept changing mg to g instead of kg
a. V^2 = Vo^2 + 2g*h = 0.
Vo^2 = -2g*h = -(-19.6)*0.18 = 3.53, Vo = 1.88 m/s.
b. KE = 0.5M*Vo^2 = 0.5*0.54*10^-6*1.88^2 = 9.54*10^-7 Joules.
Vo^2 = -2g*h = -(-19.6)*0.18 = 3.53, Vo = 1.88 m/s.
b. KE = 0.5M*Vo^2 = 0.5*0.54*10^-6*1.88^2 = 9.54*10^-7 Joules.
1 answer