clearly, -2001 <= x <= 0
Thus, 0 <= x+2001 <= 2001
So, how many numbers between 0 and 2001 are squares?
√2001 = 44.7
So, There are 45 numbers such that 0 <= x <= 44, meaning that 0 <= x^2 <= 2001
For how many different negative values of x is √x+2001 an integer?
A) 42
B) 43
C) 44
D) 45
A lot to list out, any way to find it faster??
1 answer
1 answer