For How Long Must A Current Of 1.5 Ampere Be Passed Through An Aqueous Solution Of A Copper Salt During Electrolysis In Order To Deposit 2.50g Of Copper (cu=63.5)

Answer 1

96,485 coulombs of electricity will deposit 63.5/2 or 31.25 g Cu.
Coulombs = amperes x seconds.

How many coulombs must you have? That's
96,485 x 2.5 g/31.25 g = ?
Then ? coulombs = 1.5 x seconds. You know coulombs and amperes. Solve for seconds. Post your work if you get stuck.

Answer 2

576.5g

Answer 3

For how long a current of 1.5 ampere will be passed through an aqueous solution if copper salts during electrolysis in order to deposits 2.50g of copper ( cu=63.5)