For ​g(x)equalsStartRoot left parenthesis x minus 1 right parenthesis squared EndRoot​, find ​g(7​).

Question

Question content area bottom
Part 1
A.8
8
B.5
5
C.7
7
D.6
6

Answer 1

To find \( g(7) \) for the function \( g(x) = \sqrt{(x - 1)^2} \), we first need to substitute \( x = 7 \) into the function.

1. Calculate \( x - 1 \): \[ 7 - 1 = 6 \]

2. Now substitute this value into the function: \[ g(7) = \sqrt{(6)^2} \]

3. Calculate \( (6)^2 \): \[ (6)^2 = 36 \]

4. Now take the square root: \[ g(7) = \sqrt{36} = 6 \]

Thus, the value of \( g(7) \) is \( 6 \).

The correct answer is \( \text{D. } 6 \).