f◦g = (g-1)^5 = (-6x)^5 = -7776x^5
g◦f = 1-6f = 1-6(x-1)^5 = ...
f(f(x)) = f◦f = (f-1)^5 = ((x-1)^5-1)^5
That will expand to a long 10th-degree polynomial
f^2(x) = (f(x))^2 = ((x-1)^5)^2 = (x-1)^10
f is squared, not x.
For f(x) and g(x) given below, find the following, f(x) = (x-1)^5, g(x)=1-6x
a) (f of g)(x)= -7776x^5
b) (g of f)(x)= -6x^5+30x^4-60x^3+60x^2-30x+7
c)f(f(x)=
d) f^2(x)=(f*f)(xx)=
Im stuck on c and d
1 answer
1 answer