The instructions appear quite clear, where does your problem arise?
I will do a)
Left Side = g(x+2) = 7(x+2) - 2
= 7x + 14 - 2 = 7x + 12
Right Side = g(x) + g(2)
= 7x - 2 + 12 - 2
= 7x +8
Thus g(x+2) ≠ g(x) + g(2)
do the others in a similar way
For f(x)=(3x^2)+5and g(x)=7x-2,
a. Verify: g(x + 2) ≠ g(x) + g(2).
b. Find (f – g)(x).
c. Using the resulting function in (b), show that (f – g)(2) = f(2) – g(2).
(The work should be different for each side of the equation.)
d. Is (fg)(0) =(f/g)(0)? Explain.
e. Find (f(x+h)-f(x))/h , h ≠ 0.
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1 answer