To find (f-g)(x), we need to subtract g(x) from f(x).
f(x) = 2x + 1
g(x) = x^2 - 7
(f-g)(x) = f(x) - g(x)
(f-g)(x) = (2x + 1) - (x^2 - 7)
(f-g)(x) = 2x + 1 - x^2 + 7
(f-g)(x) = -x^2 + 2x + 8
Therefore, the answer is A. -x^2 + 2x + 8.
For f(x)=2x+1 and g(x)=x^2-7, find (f-g)(x)
A.-x^2+2x+8
B.x^2-2x-8
C.-x^2+2x-6
D.2x^2-15
1 answer