would it be like this for a, and if so how would i continue that?
(f o g)(x)= 1/[(f o g)(x)-5]?
For f(x)= 1/(x-5) and g(x)= x^2+2, find:
a. (f o g)(x)
b. (g o f)(6)
5 answers
replace x by x^2+2
1/[ (x^2+2) -5 ]
= 1/(x^2 - 3)
b.
f(6) = 1/1 = 1
g(1) = 1+2 = 3
1/[ (x^2+2) -5 ]
= 1/(x^2 - 3)
b.
f(6) = 1/1 = 1
g(1) = 1+2 = 3
would it be like this for a, and if so how would i continue that?
(f o g)(x)= 1/[(f o g)(x)-5]?
=======================
no, just do what it says
f (g(x))
use g(x) = (x^2+2) for argument of f
in other words
f (x^2+2)
= 1/[ (x^2+2) - 5 ]
(f o g)(x)= 1/[(f o g)(x)-5]?
=======================
no, just do what it says
f (g(x))
use g(x) = (x^2+2) for argument of f
in other words
f (x^2+2)
= 1/[ (x^2+2) - 5 ]
Oh okay! That was very helpful. Thank you.
You are welcome :)
1 answer