To solve the problem about Sabor Farms' lettuce harvest, let's break it down as requested:
Part A:
To find the amount of sellable lettuce, we must first determine the amount that is unsellable due to spoilage. Since \( \frac{1}{9} \) of the harvested lettuce is unsellable, the mathematical expression for the amount of unsellable lettuce would be:
\[ \text{Unsellable lettuce} = 18 \cdot \frac{1}{9} \]
Then, to find the amount of sellable lettuce, we subtract the amount of unsellable lettuce from the total amount harvested:
\[ \text{Sellable lettuce} = 18 - (18 \cdot \frac{1}{9}) \]
The correct response for Part A is: A: \( 18 - (18 \cdot \frac{1}{9}) \)
Part B:
Now we will simplify the expression from Part A.
Calculating the unsellable portion: \[ 18 \cdot \frac{1}{9} = 2 \]
Now, subtract this from the total harvested: \[ \text{Sellable lettuce} = 18 - 2 = 16 \]
Thus, the amount of sellable lettuce is: B: 16 acres' worth of lettuce will be sellable this week.
So the final answers are:
- Part A: \( 18 - (18 \cdot \frac{1}{9}) \)
- Part B: 16 acres' worth of lettuce will be sellable this week.