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for equation y=2x^2+12x-10, determine the vertex, axis of symmetry, and horizontal and vertical shifts

2 answers

y= 2(x^2+6x-5)=2(x^2+6x +9) -10 -18 check that
y= 2(x+3)^2 - 28

Can you take it from here?
yeah thanks for the help
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