To determine the vertical asymptotes of y = 1/f(x), we need to find the values of x for which f(x) = 0 (since dividing by zero gives undefined values).
To find the values of x for which f(x) = 0, we can solve the quadratic equation x^2 + 4x - 12 = 0.
Using factoring, we can rewrite the equation as (x + 6)(x - 2) = 0.
Setting each factor to zero, we get x + 6 = 0 and x - 2 = 0.
Solving for x, we have x = -6 and x = 2.
Therefore, the values of x for which y = 1/f(x) will have vertical asymptotes are x = -6 and x = 2.
For each of the functions given identify the value of x for which y= 1/f(x) will have vertical asymptotes
f(x) = x^2 + 4x -12
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