#1. quadratic sequences have a constant second difference. In this case, 4. The sequence and differences are
-1, 2, 9, 20, 35, ...
...3, 7, 11, 15, ...
.....4, 4, 4, ...
So, the 1st differences form an arithmetic progression: 3 + 4k
So,
a1 = -1
an+1 = an + 3+4(n-2)
or, an+1 = an + 4n-5
#2 Since each term is just 2 more than the last, it's just an AP. List the first few terms, and it's easy to see.
4,6,8,10,...
an = 2n+2
#3 has a typo. It's either
an+1 = an * 2 or n+1 = n^2
The first case is awkward due to the negative first term.
The second case is easy. Just keep multiplying by 2: an = -4*2^n
#4 is easy, since it just means that you keep adding 3. I'm sure you can handle that.
For each of the following explicit descriptions of a sequence, find a recursive description; for the recursive ones, find an explicit rule. Assume sequences start from n = 1.
1. an = 2n2 − 3n
2. a1 = 4 and an+1 = an + 2
3. a1 = −8 and an+1 = an 2
4. an =3n
3 answers
Looks like I had mismatched subscript tags. I meant
#1. quadratic sequences have a constant second difference. In this case, 4. The sequence and differences are
-1, 2, 9, 20, 35, ...
...3, 7, 11, 15, ...
.....4, 4, 4, ...
So, the 1st differences form an arithmetic progression: 3 + 4k
So,
a1 = -1
an+1 = an + 3+4(n-2)
or, an+1 = an + 4n-5
#2 Since each term is just 2 more than the last, it's just an AP. List the first few terms, and it's easy to see.
4,6,8,10,...
an = 2n+2
#3 has a typo. It's either
an+1 = an * 2 or n+1 = n^2
The first case is awkward due to the negative first term.
The second case is easy. Just keep multiplying by 2: an = -4*2^n
#4 is easy, since it just means that you keep adding 3. I'm sure you can handle that.
#1. quadratic sequences have a constant second difference. In this case, 4. The sequence and differences are
-1, 2, 9, 20, 35, ...
...3, 7, 11, 15, ...
.....4, 4, 4, ...
So, the 1st differences form an arithmetic progression: 3 + 4k
So,
a1 = -1
an+1 = an + 3+4(n-2)
or, an+1 = an + 4n-5
#2 Since each term is just 2 more than the last, it's just an AP. List the first few terms, and it's easy to see.
4,6,8,10,...
an = 2n+2
#3 has a typo. It's either
an+1 = an * 2 or n+1 = n^2
The first case is awkward due to the negative first term.
The second case is easy. Just keep multiplying by 2: an = -4*2^n
#4 is easy, since it just means that you keep adding 3. I'm sure you can handle that.
for #3 it should be an/2