Asked by cecile
for each of following sequences state whether it converges and if it does to what limit explain your answer to the below An =(6n-3n^3)/(2n^3+4n^2) (n=1,2,3,...)
Answers
Answered by
Damon
An = 3 n (2- n^2) / [ 2 n^2 (n+2) ]
An = (3/2) (1/n) (-1) (n^2-2) /(n+2)
as n gets big, 2 looks small
An = (-3/2) (1/n) (n^2/n)
An = -3/2 (n^2/n^2)
An = -3/2
An = (3/2) (1/n) (-1) (n^2-2) /(n+2)
as n gets big, 2 looks small
An = (-3/2) (1/n) (n^2/n)
An = -3/2 (n^2/n^2)
An = -3/2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.