You need parentheses for the 2nd equation.
Is this,
y = 1/(x^2 + 5)
Or,
y = 1/(x^2) + 5
For each equation, determine whether its graph is symmetric with respect to the -axis, the -axis, and the origin.
4y^4+24x^2=28 and y=1/x^2+5
Check all symmetries that apply
x-axis,y-axis,origin or non of the above.
5 answers
Sorry y=1/(x^2+5)
4y^4 + 24x^2 = 28
Symmetric to x-axis if an equivalent equation is obtained when y is replaced by -y.
4y^4 + 24x^2 = 28
4(-y)^4 + 24x^2 = 28
4y^4 + 24x^2 = 28
Since, the two equations are equivalent, the graph is symmetric to the x-axis.
Symmetric to y-axis if an equivalent equation is obtained when x is replaced by -x.
4y^4 + 24x^2 = 28
4y^4 + 24(-x)^2 = 28
4y^4 + 24x^2 = 28
Since, the two equations are equivalent, the graph is symmetric
to the y-axis.
Symmetric to the origin if an equivalent equation is obtained when x is replaced by -x and y is replaced by -y.
4y^4 + 24x^2 = 28
4(-y)^4 + 24(-x)^2 = 28
4y^4 + 24x^2 = 28
Since, the two equations are equivalent, the graph is symmetric
to the origin.
I'll leave the 2nd equation for you to try.
Symmetric to x-axis if an equivalent equation is obtained when y is replaced by -y.
4y^4 + 24x^2 = 28
4(-y)^4 + 24x^2 = 28
4y^4 + 24x^2 = 28
Since, the two equations are equivalent, the graph is symmetric to the x-axis.
Symmetric to y-axis if an equivalent equation is obtained when x is replaced by -x.
4y^4 + 24x^2 = 28
4y^4 + 24(-x)^2 = 28
4y^4 + 24x^2 = 28
Since, the two equations are equivalent, the graph is symmetric
to the y-axis.
Symmetric to the origin if an equivalent equation is obtained when x is replaced by -x and y is replaced by -y.
4y^4 + 24x^2 = 28
4(-y)^4 + 24(-x)^2 = 28
4y^4 + 24x^2 = 28
Since, the two equations are equivalent, the graph is symmetric
to the origin.
I'll leave the 2nd equation for you to try.
I get that the second equation x-axis. Is that right?
Symmetric to y-axis if an equivalent equation is obtained when x is replaced by -x.
It is symmetric to the y-axis, not x-axis.
It is symmetric to the y-axis, not x-axis.