For diagonals of square Abcd intersect at e . If ae =2x+6 and bd =6x-10 find ac

Answer 1

The diagonals of a square bisect each other into 4 equal lengths.
AE = 2x+6 is half of a diagonal, but
BD = 6x-10 is the entire diagonal, so its half would be 3x-5

then 3x-5 = 2x+6
x = 11
so AC = BD = 6x-10 = 6(11) - 10 = 56

Answer 2

Thank you so much!

Answer 3

The diagonals of square ABCD intersect at E. If AE = 2x + 6 and BD = 6x – 10, find AC.

Answer 4

In 13-16, the diagonals of rectangle ABCD intersect at E in the diagram to the right.
13. Let and . Find AC, BD, AE, and BE.

Answer 5

It's 56