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For C2H5NH3+, write an equation that shows how the cation acts as an acid.

Why is my answer wrong?

CH2H5NH3^+(aq) + H2O(l) ---> CH2H5NH2(aq) + H3O+(aq)

4 answers

Its C2H5 and not CH2H5
Ethylamine, which you have represented as an acid, is a very weak base. The reaction that you wrote should be reversible.
You do have a typo.

CH2H5NH3^+(aq) + H2O(l) ---> CH2H5NH2(aq) + H3O+(aq)

CH5NH3^+(aq) + H2O(l) <---> CH5NH2(aq) + H3O+(aq)

Sorry, don't know how to type half arrows on this forum.
CH2H5NH3^+(aq) + H2O(l) ---> CH2H5NH2(aq) + H3O+(aq)

C2H5NH3^+(aq) + H2O(l) <---> C2H5NH2(aq) + H3O+(aq)

Sorry, don't know how to type half arrows on this forum

And I am just all over the place......