For an enclosed gas with a constant temperature, the pressure of the gas changes from 10 atm to 30 atm. What happens to the volume of the gas? a The volume becomes three times its original value. b The volume stays the same as its original value. c The volume becomes one-tenth (1/10) of its original value. d The volume becomes 10 times the original value. e The volume becomes one-third (1/3) of its original value.

Answer 1

According to Boyle's Law, the pressure and volume of an enclosed gas are inversely proportional if the temperature remains constant.

Mathematically, this can be represented as P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

In this case, the pressure changes from 10 atm to 30 atm.

Let's substitute the given values into the formula:

(10 atm)(V1) = (30 atm)(V2)

To find the relationship between the initial and final volume, we can simplify the equation:

V1 = (30 atm)(V2) / 10 atm
V1 = 3(V2)

Therefore, the volume becomes three times its original value.

So, the correct answer is (a) The volume becomes three times its original value.