x^2/a^2 + y^2/b^2 = 1 is the standard equation , and eccentricity=sqrt(1-b^2/a^2)
Here the equation is..
second point.
4/a^2=1 a=2
first point:
.4=sqrt(1-b^2/4)
.16=1-b^2/4
.64=4-b^2
b^2=3.36
x^2/4 + y^2/3.36=1
check all that work
For an ellipse, one focus is (0,0), one vertex is (2,0), and the eccentricity is 0.4. How do I find the equation for the ellipse? It seems like I have so little information!
2 answers
I get it now! However, I think you made a mistake with .16=1-b^2/4. It should be turned into .64=1-b^2, and then b^2=0.36. Then x^2/4 + y^2/0.36=1.