for an aqueous solution having Calcl2 (2molar) and Mgcl2 (5molal) and specified gravity of solution is 1.145 calculate molality of chloride ion and molality if chloride ion.

Answer 1

2 M CaCl2 = 2 mols CaCl2/L soln.
2 mol = 111 x 2 = 222 g (but that's an estimate--you recalculate it).
Use density to calculate mass of 1L soln. That will be 1145grams.
mass solvent = 1145g-222g = ?g and convert to kg. Then
mols Cl in CaCl2 = 4 (2*2)
mols Cl in MgCl2 = 10 (2*5)
Total mols Cl^- = 14
m Cl^- = mols Cl^-/kg solvent.