For a triangle ABC, find the measure of AB given m∠A = 55°, m∠B = 44°, and b = 68

a. 45.22

b. 96.68

c. 88.19

d. 81.12

1 answer

To find the measure of AB, we can use the law of sines which states:

a/sin(∠A) = b/sin(∠B) = c/sin(∠C)

Where a, b, and c are the side lengths opposite the angles A, B, and C respectively.

Using this formula, we have:

AB/sin(55°) = 68/sin(44°)

Solving for AB, we get:

AB = sin(55°) * 68 / sin(44°) ≈ 81.12

Therefore, the answer is (d) 81.12.