To find the measure of AB, we can use the law of sines which states:
a/sin(∠A) = b/sin(∠B) = c/sin(∠C)
Where a, b, and c are the side lengths opposite the angles A, B, and C respectively.
Using this formula, we have:
AB/sin(55°) = 68/sin(44°)
Solving for AB, we get:
AB = sin(55°) * 68 / sin(44°) ≈ 81.12
Therefore, the answer is (d) 81.12.
For a triangle ABC, find the measure of AB given m∠A = 55°, m∠B = 44°, and b = 68
a. 45.22
b. 96.68
c. 88.19
d. 81.12
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