For a standard normal distribution, find:

Question

P(z < c) = 0.9394

Find c rounded to two decimal places.

Answer 1

We can use the standard normal distribution table to find the value of c that corresponds to a cumulative probability of 0.9394.

Looking up 0.9394 in the table, we find that it corresponds to a z-score of approximately 1.89.

Therefore, c is approximately 1.89, rounded to two decimal places.