NH4Cl is a salt. Therefore, when dissolve it will give you (NH4^+) = 0.104M and Cl^- will be 0.104M.
Determine pH from the Henderson-Hasselbalch equation, then find H^+ from that and OH^- from (H^+)(OH^-) = Kw = 1E-14
For a solution that is 0.168 M NH3 and 0.104 M NH4Cl calculate the following.?
[OH-]
[NH4+]
[Cl-]
[H3O+]
How would you do this :-/
4 answers
But for that wouldn't you need to know the pKa?
nvm got it!
Yes. pKa for NH3 = Kw/Kb