For a simple random sample of size 19,921, the “quick method” produces a margin of error for 95%

Question

confidence of about

Answer 1

±2%, assuming a normal distribution and using the formula:

Margin of error = 1 / sqrt(sample size)

= 1 / sqrt(19,921)

= 1 / 141.19

≈ 0.0071

So the margin of error for a simple random sample of size 19,921 is approximately ±0.71%, which can be rounded to ±1%.