For a one step reaction, the activation energy for the forward reaction is 40.0 kJ mol-1, and the enthalpy of reaction is -20.0 kJ mol-1. Calculate the activation energy for the reverse reaction.

Question

Is my answer correct?
(40 kJ mol-1)-(-20 kJ mol-1) = 20kJ mol-1

Answer 1

I don't think so.
40 -(-20) = 60 and for an exothermic reaction you add Ea forward to |dH| so that is 40+20= 60 kJ/mol.