For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 12 n acts on a certain object, the acceleration of the object is 3 m/s^2. If the acceleration of the object becomes 10 m/s^2, what is the force?

Answer 1

Let's denote the initial force as F1 and the initial acceleration as a1, and the final force as F2 and the final acceleration as a2.

From the given information:
F1 = 12 N
a1 = 3 m/s^2
a2 = 10 m/s^2

According to the relationship between force and acceleration:
F1 = k * a1
F2 = k * a2

where k is a constant of proportionality.

We can find the value of k by rearranging the equation F1 = k * a1 to get:
k = F1 / a1
k = 12 N / 3 m/s^2
k = 4 Ns^2

Now, use the value of k to find the force F2 when the acceleration is 10 m/s^2:
F2 = k * a2
F2 = 4 Ns^2 * 10 m/s^2
F2 = 40 N

Therefore, the force acting on the object when the acceleration is 10 m/s^2 is 40 N.