For a lottery game, each ticket has a probability of 1 / 3.09 = 0.324 of winning a prize. Every friday you buy 1 lottery game.

Question

a) What is the probability you will win on two of your next three games?

Answer 1

p = p win = .324
1-p = p lose = .676

binary distribution

P(x = k) = C(n,k) p^k (1-p)^(n-k)
C(2,3) = 3!/2!(3-2)! = 3
so
= 3(.324)^2 (.676)
= .213