surface area=PI*r*hs + PI*r^2
radius=4x hs=1/6 x
modified area=2PI*hs/3 + PI (16)r^2 where r, hs are the original slant heights, and radius.
For a cone, if the radius was quadrupled and the slant height was reduced to one sixth of its original size, what would be the formula to find the modified surface area?
1 answer