For a class project, Jerome builds a simple circuit with a battery and three light bulbs. On his way to school, Jerome drops his project and breaks one of the light bulbs. He has no time to fix or replace the bulb, so he removes the broken bulb and turns in his project. What will happen when Jerome runs current through his circuit?

Question

a
If Jerome built a series circuit, only the remaining bulb closest to the battery will light up.
b
If Jerome built a parallel circuit, both remaining bulbs will still light up.
c
If Jerome built a series circuit, both remaining bulbs will still light up.
d
If Jerome built a parallel circuit, only the remaining bulb closest to the battery will light up.

Answer 1

The correct answer is c) If Jerome built a series circuit, both remaining bulbs will still light up.

In a series circuit, the current flows through the components in a single path. If one component stops functioning or is removed, it breaks the circuit and interrupts the flow of current. Therefore, in this case, if one bulb is removed, the circuit will be broken and no bulbs will light up. Hence, option a) and b) are not correct.

On the other hand, in a parallel circuit, each component is connected separately to the battery, so the removal of one bulb will not affect the other bulbs. Both remaining bulbs will still light up. Therefore, option d) is also not correct.