For a certain reaction ∆H is 54 kJ/mol and ∆S is 128 J/mol · K. This reaction can become spontaneous only above some temperature.

Question

For a certain reaction ∆H is 54 kJ/mol and ∆S is 128 J/mol · K. This reaction can become spontaneous only above some temperature.
What is this temperature?
Answer in units of ◦C.

DrBob222 · Answer

dG = dH - TdS If dG = 0, then TdS = dH. Solve for T. Watch the units. dH is in kJ/mol and dS in J/mol