For 10 consecutive days, Anthony recorded the daily high temps in Daytona and Laredo. The table shows the data.

Question

Daily high temps in F
Daytona 77 82 85 87 90 85 79 86 91 88
Laredo 81 79 80 86 88 92 82 88 84 87

Answer 1

To find the average daily high temperature for each city over the 10-day period, we add up all the temperatures and divide by 10.

For Daytona:
77 + 82 + 85 + 87 + 90 + 85 + 79 + 86 + 91 + 88 = 860
Average temperature for Daytona = 860 / 10 = 86°F

For Laredo:
81 + 79 + 80 + 86 + 88 + 92 + 82 + 88 + 84 + 87 = 849
Average temperature for Laredo = 849 / 10 = 84.9°F

Therefore, the average daily high temperature over the 10-day period was 86°F in Daytona and 84.9°F in Laredo.

Answer 2

(1 point)
Responses

Laredo has a higher median daily high temperature than Dayton by 1°F
Laredo has a higher median daily high temperature than Dayton by 1degreeF

Laredo has a higher median daily high temperature than Dayton by 0.5°F
Laredo has a higher median daily high temperature than Dayton by 0.5degreeF

Dayton has a higher median daily high temperature than Laredo by 0.5°F
Dayton has a higher median daily high temperature than Laredo by 0.5degreeF

Dayton has a higher median daily high temperature than Laredo by 0.3°F

Answer 3

To find the median daily high temperature for each city, we first arrange the temperatures in ascending order.

For Daytona: 77, 79, 82, 85, 85, 86, 87, 88, 90, 91
The median for Daytona is the middle value, which in this case is 85.

For Laredo: 79, 80, 81, 82, 84, 86, 87, 88, 88, 92
The median for Laredo is also the middle value, which in this case is 86.

Therefore, Laredo has a higher median daily high temperature than Daytona by 1°F.

Answer 4

The following data set represents the highway fuel efficiency in miles per gallon (mpg) of randomly selected cars from two car
companies.
Car Company A: 35, 28, 35, 30, 31, 38, 35, 30
Car Company B: 29, 33, 36, 27, 34, 34, 34, 25
Which of the following statements is true?
(1 point)
Responses

The cars from Company A have higher MEDIAN highway fuel efficiency than Company B.
The cars from Company A have higher MEDIAN highway fuel efficiency than Company B.

The cars from Company A have higher MEAN highway fuel efficiency than Company B.
The cars from Company A have higher MEAN highway fuel efficiency than Company B.

The cars from Company B have a higher MODE of highway fuel efficiency than Company A.
The cars from Company B have a higher MODE of highway fuel efficiency than Company A.

The cars from both companies have the same mean, median, and mode for highway fuel efficiency.

Answer 5

To determine the median, mean, and mode for each car company:

For Company A: 35, 28, 35, 30, 31, 38, 35, 30
Median: Arranging the numbers in ascending order, we get 28, 30, 30, 31, 35, 35, 35, 38. The median is the middle number, which is 32.5.
Mean: (35 + 28 + 35 + 30 + 31 + 38 + 35 + 30) / 8 = 32.625
Mode: The mode is 35 as it appears most frequently.

For Company B: 29, 33, 36, 27, 34, 34, 34, 25
Median: Arranging the numbers in ascending order, we get 25, 27, 29, 33, 34, 34, 34, 36. The median is the middle number, which is 33.5.
Mean: (29 + 33 + 36 + 27 + 34 + 34 + 34 + 25) / 8 = 31.625
Mode: The mode is 34 as it appears most frequently.

Based on the calculations:
- The cars from Company A have a higher median highway fuel efficiency than Company B.
- The cars from Company A do not have a higher mean highway fuel efficiency than Company B as the mean for Company B is slightly higher.
- The cars from Company B do not have a higher mode of highway fuel efficiency than Company A as the mode is the same for both companies.

Therefore, the statement "The cars from Company A have higher MEDIAN highway fuel efficiency than Company B" is true.