e^(0.03k) = 1.4
0.03k*Lne = Ln1.4
0.03k*1 = 0.33647
k = 11.22
For # 1, im getting stuck on this problem i don't understand this
1.4 = e ^ (0.03k)
Now take the natural logarithm of both sides to solve for ,
ln 1.4 = ln e ^ (0.03k)
ln 1.4 = 0.03k * ln e
Recall that ln e = 1.
ln 1.4 = 0.03 k
Solve for k.
Then try part b.
For # 2,
y = 3 + e ^ (4 - x). Swap x and y and then solve for y.
x = 3 + e ^ (4 - y)
x - 3 = e ^ (4 - y)
Now take the natural logarithm of both sides and solve for y.
1 answer