a) needs work. What you have plus Zn^+2 and Al^+3.
b) is ok.
Here is a site that explains the hydrolysis of metal hydrate ions (which you have with Al(H2O)6^+3 and Zn hydrates). Set up an ICE chart for these two which should allow you to calculate both H^+ and Ka. There is no hydrolysis for the anions UNLESS you want to get fancy and go through the SO4^-2 to produce HSO4^-.
For 0.10 M ZnCl2 and 0.10 M KAl(SO4)2, find:?
a) spectator ions (if any)
b) ions expected to hydrolyze (if any)
c) net ionic equation for hydrolysis
d) expression for equilibrium constant (Ka or Kb)
e) value of Ka or Kb
My answers are:
a) Cl- ; K+ ; SO4^2-
b) Zn+ ; Al3+
please help me c); d); and e)
2 answers
Dr Bob's response says the Zn and Al should be added to a) the spectator ions, and also be answer to b) the ions which will hydrolyze. How can they be both?