Follinwing this procedure:
1. Obtain a burette. Rinse it by pouring water through it. Add 15 ml of the HCl into the burette. Hold the burette horizontal and swirl it to further prepare it for the experiment. Pour this acid down the drain.
2. Place the burette in a clamp. With a funnel slowly add approx. 50 mL of the HCL to the burette. Make sure that it flows freely by discarding about 2 mL of acid by opening the valve.
3. Use a pipette to transfer 10 mL of your dilute base to a clean flask (i'm assuming the bas is NaOH).
4. We are using the acid in the burette because the base clogs the valves. You will use a fresh 10 ml of base in the flask for each trial. You will add the indicator provided, add just enough drops to make the colour easy to distiguish your base. You will do at least 3 trials. The first one is a calibration trial. IT is done fairly fast to get a rough idea of how much acid is neede to neutralize the 10 ml of base. The following trials are done more carefully. As your titration approaches neutralization, slow the valve down to a drop by drop speed.
Do enough trials so you have a percent difference of 5%.
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So i did all of this in class, and i did 3 trials obviously, and i did not got a 5% reading, but that was because my indicator was not very well and my teacher said that was okay as long as i did everything else right.
My Initial reading for the calibration run was 1.2 ml, for trial 1 it was 2.0 ml and for trial 2 it was 1.2 ml. My final reading for the calibration run was 37.2 ml, for trial 1 it was 39.1 ml and for trial 2 it was 31.8 ml. The final readings for calibration run were 36.0 ml and for trial 1 it was 37.1 and for trial 2 it was 30.6
So what i need to know:
1. what is the ratio of hydrogen ions to hydroxide ions?
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