FOA A F24 Unit 2 Test Retake

4 of 194 of 19 Items

Question
Hal used the following procedure to find an estimate for
.

Step 1: Since
and
and
, then
is between 7 and 8.

Step 2: Since 51.8 is closer to 49, square the tenths closer to 7.

Step 3: Since
, square the hundredths closer to 7.2



Step 4: Since 51.8 is closer to 51.6961 than it is to 51.84, 7.19 is the best approximation for
.

Did Hal make an error? If so, in which step?

Responses

In Step 1,
is between 6 and 9 because
and
.
In Step 1, square root of 51 point 8 is between 6 and 9 because square root of 51 point 8 approximates square root of 52 and 6 times 9 is equal to 54.

Hal did not make an error.
Hal did not make an error.

In Step 4, he made an error in selecting the correct decimal approximation.
In Step 4, he made an error in selecting the correct decimal approximation.

In Step 2, he made a calculation error when squaring.
In Step 2, he made a calculation error when squaring.

1 answer

To determine if Hal made an error in his estimation procedure for \(\sqrt{51.8}\), let's analyze each step:

Step 1: Hal stated that since \(49 < 51.8 < 64\) (where \(7^2 = 49\) and \(8^2 = 64\)), then \(\sqrt{51.8}\) is between 7 and 8. This is correct.

Step 2: Hal indicated that \(51.8\) is closer to \(49\) and suggested squaring the tenths closer to \(7\). However, this sentence is not clearly written. The focus should be on determining the approximate value of \(\sqrt{51.8}\) by estimating rather than squaring. Thus, while he is trying to narrow it down, this step is somewhat unclear. It would be more straightforward to say that he is trying to narrow it down to find the square roots close to \(7.2\) which could be a step in estimating.

Step 3: In this step, he mentions squaring the hundredths closer to \(7.2\). Let's assume he meant to evaluate \(\sqrt{51.8}\) and mention approximating it toward \(7.2\), which is reasonable since \(7.2^2 = 51.84\) and that is close to \(51.8\); this part of reasoning seems coherent.

Step 4: He claims that \(51.8\) is closer to \(51.6961\) than it is to \(51.84\) (where \(7.19^2 = 51.6961\)). Given \(51.8\) is indeed closer to \(51.84\), he incorrectly selects \(7.19\) as the best approximation. The closer approximation should have been \(7.2\) since it squares to \(51.84\) which is actually nearer to \(51.8\).

Conclusion:

Hal made a mistake in Step 4, where he inaccurately selected the approximation by saying \(7.19\) is the best approximation for \(\sqrt{51.8}\). The correct selection should have been \(7.2\), since it offers a closer square to \(51.8\) than \(7.19\).

Correct response: In Step 4, he made an error in selecting the correct decimal approximation.

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