Five ul of a 10 to 1 dilution sample was added to 3ml of Bradford reagent. The absorbable reading was 0.68. According to the standard curve this represents 0.05mg of protein. Determine the stock concentration of the protein solution in mg/ml

Answer 1

To determine the stock concentration of the protein solution in mg/ml, we need to calculate the concentration of the diluted protein solution first.

First, let's calculate the concentration of the diluted protein solution in mg/ml:
- The absorbance reading is 0.68.
- According to the standard curve, this corresponds to 0.05 mg of protein.
- Therefore, the concentration of the diluted protein solution is (0.05 mg) / (3 ml) = 0.0167 mg/ml.

Now, let's calculate the concentration of the stock protein solution in mg/ml:
- The diluted protein solution was prepared by adding 5 ul of the stock protein solution to 3 ml of Bradford reagent.
- The dilution factor is (3 ml) / (5 ul) = 600.
- Therefore, the concentration of the stock protein solution is 0.0167 mg/ml * 600 = 10 mg/ml.