five mole of an ideal gas are kept at a constant temperature of 53 degree celcius while the pressure of the gas is increased from 1 atm to 3 atm calculate the work done by the gas

Answer 1

At constant T, Volume V is inversely proportional to P. Therefore
PV = P1*V1
Compute V1 first of all
V1 = nRT/P1 = 134 liters = 0.134 m^3
P1 = 1 atm = 1.013*10^5 N/m^2

Work done on gas =
-Integral of P dV = -P1*V1 Integral of dV/V
= P1*V1 ln (V1/V2) = P1*V1*ln(P2/P1)
= P1*V1 ln3 = 1.49*10^4 Joules

Answer 2

Your ans is wrong