Asked by Senior

Five forces act on an object.
(1) 65 N at 90°
(2) 40 N at 0°
(3) 79 N at 270°
(4) 40 N at 180°
(5) 50 N at 60°
What are the magnitude and direction of a sixth force that would produce equilibrium?

_____ N at _____°
Answered by R_scott
(1) + (3) = 14 N @ 270º

(2) + (4) = 0

resolve 50 N @ 60º into 0º and 90º components

combine with 14 N @ 270º

the equilibrium force will have the same magnitude, but opposite direction
Answered by Henry2
Fr = 65i + 40 + (-79i) + (-40) + (25 + 43.3i) = 25 + 29.3i = 38.5N[49.5] N. of E. = 49.5 CCW. = Resultant force.

Fe = 38.5N.[49.5+180] = 38.5 N.[229.5o] CCW. = Equilibrant force.


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