Five cards are lettered A,B,C,D,E.Three cards are chosen at random,one after the other,without replacement and are placed in the order shown in fig11.6

Answer 1

There is no figure provided, but I will assume the order shown is A, B, C.

The probability of selecting A as the first card is 1/5.
After selecting A, there are 4 cards left, so the probability of selecting B next is 1/4.
After selecting A and B, there are 3 cards left, so the probability of selecting C last is 1/3.

Therefore, the overall probability of selecting A, B, C in that order is:
1/5 x 1/4 x 1/3 = 1/60

So, the probability of selecting A, B, C in that order is 1/60.