The 35 m of horizontal travel in 3.0 s tell you the horizontal velocity component, 11.67 m/s. The hose angle is the angle whose cosing is 11.67/27.0
At the highest point of the trajectory, the water's vertical velcoity component is zero. You should know what the horizintal component is.. it does not change.
Try to do the rest of this yourself. It is very smiliar to the other questions you have posted this evening. You learn more by doing than by having work done for you.
Firemen are shooting a stream of water at a burning building. A high-pressure hose shoots out the water with a speed of 27.0m/s as it leaves the hose nozzle. Once it leaves the hose, the water moves in projectile motion. The firemen adjust the angle of elevation of the hose until the water takes 3.00s to reach a building 35.0m away. You can ignore air resistance; assume that the end of the hose is at ground level.
Find the speed of the water at the highest point in its trajectory.
How high above the ground does the water strike the building?
How fast is it moving just before it hits the building?
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